Python CONNECT 4 CHECK WIN函数
本文介绍了Python CONNECT 4 CHECK WIN函数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在编写一个连接4游戏,在其中您可以选择棋盘的大小。这个游戏对于大多数棋盘大小都能完美地运行,但当棋盘比棋盘宽时,我会遇到问题。我不断得到索引超出范围的错误,我不确定我做错了什么。这就是我目前的支票功能,因为它是唯一有问题的部分。
def checkOWin(board):
boardHeight = len(board)
boardWidth = len(board[0])
tile = 'O'
# check horizontal spaces
for y in range(boardHeight):
for x in range(boardWidth - 3):
if board[x][y] == tile and board[x+1][y] == tile and board[x+2][y] == tile and board[x+3][y] == tile:
return True
# check vertical spaces
for x in range(boardWidth):
for y in range(boardHeight - 3):
if board[x][y] == tile and board[x][y+1] == tile and board[x][y+2] == tile and board[x][y+3] == tile:
return True
# check / diagonal spaces
for x in range(boardWidth - 3):
for y in range(3, boardHeight):
if board[x][y] == tile and board[x+1][y-1] == tile and board[x+2][y-2] == tile and board[x+3][y-3] == tile:
return True
# check diagonal spaces
for x in range(boardWidth - 3):
for y in range(boardHeight - 3):
if board[x][y] == tile and board[x+1][y+1] == tile and board[x+2][y+2] == tile and board[x+3][y+3] == tile:
return True
return False
如有任何帮助或建议,将不胜感激。提前感谢!
推荐答案
您刚刚混淆了维度,您应该这样设置它们:
def checkOWin(board):
boardHeight = len(board[0])
boardWidth = len(board)
因为当您引用board[x]时,这是计算董事会中列表的数量,而当您引用board[x][y]时,只是指董事会中某一特定行的长度。
if board[x][y] == tile and board[x+1][y] == tile and board[x+2][y] == tile and board[x+3][y] == tile:
当我翻转这些值时,函数运行没有错误。
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